2x/(x+3)+6/x=18/(x^2+3x)

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Solution for 2x/(x+3)+6/x=18/(x^2+3x) equation:


D( x )

x^2+3*x = 0

x = 0

x+3 = 0

x^2+3*x = 0

x^2+3*x = 0

x^2+3*x = 0

DELTA = 3^2-(0*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-3)/(1*2) or x = (-9^(1/2)-3)/(1*2)

x = 0 or x = -3

x = 0

x = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:0) U (0:+oo)

(2*x)/(x+3)+6/x = 18/(x^2+3*x) // - 18/(x^2+3*x)

(2*x)/(x+3)-(18/(x^2+3*x))+6/x = 0

(2*x)/(x+3)-18*(x^2+3*x)^-1+6/x = 0

(2*x)/(x+3)-18/(x^2+3*x)+6/x = 0

x^2+3*x = 0

x^2+3*x = 0

x*(x+3) = 0

x+3 = 0 // - 3

x = -3

x*(x+3) = 0

(2*x)/(x+3)-18/(x*(x+3))+6/x = 0

(2*x*x)/(x*(x+3))-18/(x*(x+3))+(6*(x+3))/(x*(x+3)) = 0

6*(x+3)+2*x*x-18 = 0

2*x^2+6*x-18+18 = 0

2*x^2+6*x = 0

2*x^2+6*x = 0

2*x*(x+3) = 0

x+3 = 0 // - 3

x = -3

2*x*(x+3) = 0

(2*x*(x+3))/(x*(x+3)) = 0

(2*x*(x+3))/(x*(x+3)) = 0 // * x*(x+3)

2*x*(x+3) = 0

( 2*x )

2*x = 0 // : 2

x = 0

( x+3 )

x+3 = 0 // - 3

x = -3

x in { 0}

x in { -3}

x belongs to the empty set

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